tag:blogger.com,1999:blog-5303307482158922565.post6065036429659139158..comments2018-02-12T11:30:22.535-08:00Comments on Math Mama Writes...: Murder Mystery: A Project for LogarithmsSue VanHattumhttp://www.blogger.com/profile/10237941346154683902noreply@blogger.comBlogger67125tag:blogger.com,1999:blog-5303307482158922565.post-16550595914397762912017-11-16T08:34:53.898-08:002017-11-16T08:34:53.898-08:00Yes my regression does take the data down to 0. Wh...Yes my regression does take the data down to 0. What algebra steps are used to solve this. I know that at whatever time zero the body is 98.6. ...<br />I got it now. ThanksJosephhttps://www.blogger.com/profile/06455349495917896426noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-16586838878542139622017-11-16T07:04:17.264-08:002017-11-16T07:04:17.264-08:00>The data follows an exponential graph but take...>The data follows an exponential graph but takes the data down to 0.<br /><br />It sounds like you mean that your regression takes the graph down to 0. If you want to use regression, instead of doing the algebra, you would need to use excess heat (how high above room temp) as your y values.<br />Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-5834537033327713882017-11-16T06:40:04.722-08:002017-11-16T06:40:04.722-08:00I would figure that the temperature would bottom o...I would figure that the temperature would bottom out at room temperature or 80 degrees on the island. Also, I would figure 98.6 being the temperature just prior to death. The data follows an exponential graph but takes the data down to 0. So when the cup of coffee gets to 2 or 3 hours the temp should be room temp but using the model my regression takes it down to zero. <br />I have tried working some transformations using the equation I find but am at a loss as to how to fix the issue. Josephhttps://www.blogger.com/profile/06455349495917896426noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-8718914438970930702017-07-10T07:55:14.271-07:002017-07-10T07:55:14.271-07:00None of my students has paid enough attention to n...None of my students has paid enough attention to notice this.I would ask: Do different cups of coffee cool at different rates? What does it depend on?<br /><br />I'm guessing the first person had more insulating body fat (thicker coffee cup), and the second person was smaller overall. <br /><br />But that difference does seem big. I have always just made up the temps, and then found the time and made sure it worked with the clues. Maybe I should keep them closer to one another. I just looked up body cooling (again), and you must tell student this is an oversimplification of real life.<br /><br />I re-read what you wrote, and it's important to say "in the first hour" and never say "per hour". That would indicate a constant rate of change. Every time a student says a thing like that I ask what they think will happen in the second hour, and we return to the graph. Students are so used to straight lines, they want to treat everything the way they do straight lines.<br />Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-82149137409188577492017-07-10T07:11:25.933-07:002017-07-10T07:11:25.933-07:00Hi Sue,
I am working through this project to do w...Hi Sue,<br /><br />I am working through this project to do with my students and have a question that I can't seem to resolve: In the first set of data, the body temperature decreases at a rate of 4.4 degrees in one hour. In the second set of data (assignment 4), the body temperature decreases at a rate of 5.9 degrees in 30 minutes or 11.8 degrees per hour. Since it has a lower starting body temp when found, shouldn't it be decreasing more slowly than the first body found?Denisenoreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-58106021597398081292017-01-24T06:24:22.403-08:002017-01-24T06:24:22.403-08:00By the time of my death. (I am imagining you awake...By the time of my death. (I am imagining you awake now, and seeing it yourself without this comment...)Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-51665310505844355012017-01-24T01:27:22.769-08:002017-01-24T01:27:22.769-08:00Hello Sue!
Quick question!
Granted, I'm read...Hello Sue!<br /><br />Quick question!<br /><br />Granted, I'm reading this at 4 a.m. and might be overlooking something very simply in my exhaustion. However, I am trying to follow the project (which is amazing, by the way) and I get stuck on Assignment 4. If you've narrowed it down to 4 suspects, and then in step 4, split them up into 4 groups (one per group) you would be able to determine the killer if you could determine which group of the four is unaccounted for. Totally get that. But how do you determine which of the four groups is the one without the alibi? The assignment just seems to stop there. <br /><br />Thanks!Cassandra Poulinhttps://www.blogger.com/profile/10626472874312204832noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-70591461495333836702015-05-25T06:34:47.779-07:002015-05-25T06:34:47.779-07:00I want the answers .!
I want the answers .!<br />Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-84276575067725381372015-05-08T07:41:36.911-07:002015-05-08T07:41:36.911-07:00The problem can't be solved with the informati...The problem can't be solved with the information given. The person using the problem with students needs to add more students (and change all the names). If you're a teacher, please let me know what more you would need to use this. If you don't understand exponential functions and how that relates to cooling off, don't use this in a classroom. You can see in the comments above that a very irresponsible teacher used this just as it is, which makes no sense.<br /><br />Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-69823053873702116772015-05-08T05:20:58.891-07:002015-05-08T05:20:58.891-07:00I need help I'm stuckI need help I'm stuckJessica Vigilhttps://www.blogger.com/profile/09402698019243853466noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-64585713120468626152015-03-02T20:39:19.373-08:002015-03-02T20:39:19.373-08:00What do you think?What do you think?Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-34033359347111257572015-03-02T15:40:11.829-08:002015-03-02T15:40:11.829-08:00is it kevin
is it kevin<br />Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-16670802829882856682014-03-30T20:44:38.721-07:002014-03-30T20:44:38.721-07:00Are you telling me you have no access to a way to ...Are you telling me you have no access to a way to heat water up? You can at least test the time, can't you?Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-74065061995454969132014-03-30T20:30:31.455-07:002014-03-30T20:30:31.455-07:00What do you think, Nelson? (And if you're not ...What do you think, Nelson? (And if you're not old enough to drink coffee, ask someone who is. Or google it. Or google the time McDonald's got sued because someone got burned by their coffee. Lots of options. No need to ask here.) You could buy a cup of coffee to see how long it takes to get cold. Or you could heat up some water, and check that.<br /><br />Sorry if I sound snippy. I am concerned because I've also gotten questions in email that seem like people don't want to think. I'm not sure yet what I want to do about it...<br />Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-8907617729020678062014-03-30T20:24:00.530-07:002014-03-30T20:24:00.530-07:00This comment has been removed by the author.Nelsonhttps://www.blogger.com/profile/16299664747490212402noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-66666024385679587262014-02-07T11:18:45.786-08:002014-02-07T11:18:45.786-08:00I don't understand. Email me to discuss answer...I don't understand. Email me to discuss answer if you want. (mathanthologyeditor on gmail)Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-87684347989049689112014-02-07T11:08:33.570-08:002014-02-07T11:08:33.570-08:00It was exactly what you posted here. The time she ...It was exactly what you posted here. The time she got was roughly an hour after the second pair. She said that the 3rd pair went by after the body was discovered and so they can't be suspects. So it was very confusing to find 2 pairs of suspects. They were supposed to make a poster for the puzzle. She did everything in the poster with out writing the suspects or the murderer. Just wrote the titles, suspects and murderer and wanted to ask the teacher about this part before completing it. When she went to ask her, the teacher has asked her to turn it in for a lower grade as she didn't complete it. Never answered her question too. I didn't check her answers, but I am pretty sure she got the answers right. Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-7890700906235505912014-02-07T10:32:27.269-08:002014-02-07T10:32:27.269-08:00No, that's why I said I list the rest of the c...No, that's why I said I list the rest of the class in between. The way I do it is to put students in pairs, and have one pair walk by every few (say 4 to 15) minutes. I make sure none walks by at exactly the right time, so there are two pairs who are suspects. The second murder splits everyone up, so only one person is a suspect for both murders.<br /><br />Did the teacher use the names I gave here, instead of the kids in the class?Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-24983078529063290832014-02-07T10:28:32.223-08:002014-02-07T10:28:32.223-08:00My daughter got this project for her 8th grade mat...My daughter got this project for her 8th grade math class. The teacher gave only the 3 pairs that you have mentioned in this for assignment 3. The time of murder she got is not very close to any of the three values and she thinks the in between values for the other pairs should be there to find the true murderer. The time (given), closest to the value she got is about 1 hr before the murder. Are the 3 times given in your problem enough to find the murderer? Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-25495009115859029542014-02-04T17:32:22.863-08:002014-02-04T17:32:22.863-08:00Nope. The teachers can figure out the math. And I ...Nope. The teachers can figure out the math. And I don't want it searchable for students. You are welcome to email me with particular questions.Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-87413583972206678132014-02-04T17:30:43.914-08:002014-02-04T17:30:43.914-08:00Hey Sue,looks like a great project, do you have an...Hey Sue,looks like a great project, do you have an answer key for this you can post?Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-65165592102791501092014-01-10T15:40:59.581-08:002014-01-10T15:40:59.581-08:00I tried to email you and it bounced. Try emailing ...I tried to email you and it bounced. Try emailing me directly (mathanthologyeditor on gmail).Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-27484659284168827032014-01-10T14:19:31.894-08:002014-01-10T14:19:31.894-08:00Sue,
I am wondering if you happen to have even m...Sue, <br /><br />I am wondering if you happen to have even more information about this project, or any sort of additional materials you use. This looks like a fun project and I would like to start it next week but have very limited time to put things together this week. My email is aderosa@mancosre6.edu. Thank you! AMDW1024https://www.blogger.com/profile/03703404938143761562noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-16247567102337184112013-10-22T07:42:40.834-07:002013-10-22T07:42:40.834-07:00I found my mistake. Don't you know it was in t...I found my mistake. Don't you know it was in the arithmetic, not in the mathematics. Thanks for this fun activity!Anne Chttps://www.blogger.com/profile/02115466582446190655noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-17796470592110171502013-10-21T15:50:23.712-07:002013-10-21T15:50:23.712-07:00I just edited the post to point to a soundtrack on...I just edited the post to point to a soundtrack on youtube. Thanks for pointing that out.<br /><br />Email me with the steps you took, and I'll point to your mistake. (suevanhattum on hotmail)Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.com