tag:blogger.com,1999:blog-5303307482158922565.comments2019-06-14T10:17:45.734-07:00Math Mama Writes...Sue VanHattumhttp://www.blogger.com/profile/10237941346154683902noreply@blogger.comBlogger2162125tag:blogger.com,1999:blog-5303307482158922565.post-84295055961757978362019-06-14T10:17:45.734-07:002019-06-14T10:17:45.734-07:00Is this coming from my old friend in Muskegon?Is this coming from my old friend in Muskegon?Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-42833309129070657392019-06-14T07:42:45.366-07:002019-06-14T07:42:45.366-07:00a salute to ur thoughts dear sue....a true example...a salute to ur thoughts dear sue....a true example of third eye this is. Thank you for sharing with all of us.<br />Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-83257603127800615302019-04-02T14:06:29.402-07:002019-04-02T14:06:29.402-07:00You can't tell which island I'm from, sinc...You can't tell which island I'm from, since they'd all say that. And it was my goofy way of saying there are no April Fool's jokes in this post.<br /><br />For a statement like that one to make sense, a truthteller would have to say the liar would say X (where X is a lie), and the liar would have to say that the truthteller would tell a lie. So X must be a lie.<br /><br />I don't know if my explanation helps any...Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-20125428898082091182019-04-02T13:16:18.564-07:002019-04-02T13:16:18.564-07:00Thank you so much for hosting! I love the posts yo...Thank you so much for hosting! I love the posts you found. <br /><br />As for your April Fool's question --- Augh! "People from the other island" statements always make my head spin, but with the possibility of a joke built in... I wonder, would Truthtellers even allow themselves to make a joke?Denise Gaskinshttps://www.blogger.com/profile/11928843626113889088noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-67583865102601660462019-04-01T14:47:18.371-07:002019-04-01T14:47:18.371-07:00Am I from the Island of Truthtellers or the Island...Am I from the Island of Truthtellers or the Island of Liars? I say "People from the other island would tell you there's an April Fool's Joke here."Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-39208544164268600802019-02-04T15:37:29.747-08:002019-02-04T15:37:29.747-08:00It looks like that may be where the puzzle I featu...It looks like that may be where the puzzle I featured in my post came from! I didn't know this book. Thanks for sharing. I have ordered a copy.Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-60226159726529932352019-02-04T09:33:28.774-08:002019-02-04T09:33:28.774-08:00Hi! Do you know the Area Mazes Book?
https://book...Hi! Do you know the Area Mazes Book?<br /><br />https://books.google.com.br/books?id=fFZeDgAAQBAJ&printsec=frontcover&hl=pt-BR&source=gbs_ge_summary_r&cad=0#v=onepage&q&f=falseHumberto Bortolossihttps://www.blogger.com/profile/08218059136324543967noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-3439415539844770552019-01-29T09:38:05.411-08:002019-01-29T09:38:05.411-08:00By coincidence I was working on this too back in D...By coincidence I was working on this too back in December: https://mymathclub.blogspot.com/2018/12/proof-of-pentagon-construction.html and used some ideas from cut the knot as well. +1 on mathjax/Latex for blogging (I use it in the above post)Benjamin Leishttps://www.blogger.com/profile/10974191081762367425noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-52682909838019928392019-01-15T22:11:50.836-08:002019-01-15T22:11:50.836-08:00Email me if you can do it this coming week. I need...Email me if you can do it this coming week. I need the ratings by next Wednesday, January 23.Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-75261331462956762932019-01-15T21:38:26.584-08:002019-01-15T21:38:26.584-08:00I am willing to help! Is there a time frame you ha...I am willing to help! Is there a time frame you have in mind?mathematicamamahttps://www.blogger.com/profile/16356858870112804877noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-85613453140099655742018-11-28T20:09:41.902-08:002018-11-28T20:09:41.902-08:00Newton-Raphson (which was known long before Newton...Newton-Raphson (which was known long before Newton or Raphson) makes figuring square-roots by hand not too bad. 192.7 is close to 14^2 (196), so the 2nd estimate would be 14 - (14^2-192.7)/28 = 14-33/280 = 3887/280. This turns out to be about 0.0005 off of the actual square root of 192.7. It converges quadratically, so the number of accurate digits roughly doubles with each iteration.<br /><br />I recently came across a problem that was of the form (1/log_a x) + (1/log_{a^2} x) + ... + (1/log_{a^k} x) = C, with the challenge to solve for x. That becomes much easier if you know the identity log_x y = 1/log_y x. The LHS becomes log_x a + log_x a^2 + ... + log_x a^k = log_x a^{1+2+...+k} = (k(k+1)/2) log_x a, which means that log_a x = k(k+1)/(2C). With proper choice of a, k and C this problem can look hard, but work out really easy.Buddha Buckhttps://www.blogger.com/profile/17167036913705912859noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-63385723784314749232018-10-29T19:49:29.585-07:002018-10-29T19:49:29.585-07:00I have never played these two games, but it sounds...I have never played these two games, but it sounds very interesting, maybe I will try it for Christmas.Melvin P. Orrhttps://www.tomtop.com/p-f1898.htmlnoreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-62966979790682320942018-09-11T18:38:33.865-07:002018-09-11T18:38:33.865-07:00Yes! I played at it years ago, and thought I menti...Yes! I played at it years ago, and thought I mentioned it in a post. But I don't find any previous mention of it on my blog. Thanks! I am playing now. The sciencevsmagic is smaller, and easier to conceive of finishing. I liked it better before. But this one is great too, and I just figured out the rhombus in a rectangle. Yay.Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-3078109228552256832018-09-11T15:49:23.564-07:002018-09-11T15:49:23.564-07:00Euclidea is also awesome.Euclidea is also awesome.mathematicamamahttps://www.blogger.com/profile/16356858870112804877noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-6917591349617978402018-09-09T20:24:45.360-07:002018-09-09T20:24:45.360-07:00My friend, Barbara, decided to try this in autocad...My friend, Barbara, decided to try this in autocad. She had trouble commenting. Here's what she says:<br /><br />I figured out how to construct a pentagram in AutoCad using only lines and circles (equiv. of straight edge and compass). (I'm actually using Draftsight which is a free clone of 2d AutoCad.) I figured out that the key internal element is the 36-72-72 triangle (apparently called the Golden Triangle). Once I figured out how to construct a 36-72-72 triangle the pentagon was easy. But I didn't find the key move at all intuitive. I had to cheat and look stuff up. But I learned stuff I didn't know (not much call to construct pentagons in civil engineering). I made a Quicktime movie for you. It's big so I put it on Google Drive. Here's the link: <br />https://drive.google.com/file/d/1jZVa01-aS1ZGuqcfySz5iRkh3qLJOe_6/view?usp=sharingSue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-7557500827145051992018-09-08T18:40:27.644-07:002018-09-08T18:40:27.644-07:00Thanks for sharing the sciencevsmagic website. It&...Thanks for sharing the sciencevsmagic website. It's a perfect addition to my arsenal for Fun Math Fridays. And it's great fun to play with, regardless of your age!Nataliehttps://www.blogger.com/profile/15849196211716308785noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-87329006589153728742018-09-02T19:36:58.686-07:002018-09-02T19:36:58.686-07:00I got that one this time around. And I finally got...I got that one this time around. And I finally got the pentagon. But I was following directions for that one. Now I'm working on understanding a proof that those directions work. I think it's the only one that needs algebra to understand.Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-63938615309971331922018-08-30T17:05:02.189-07:002018-08-30T17:05:02.189-07:00I bet you gave google your email to make this comm...I bet you gave google your email to make this comment. But I don't get to see it. So I can't email you. But you can email me. mathanthologyeditor at gmail. I'd be happy to give you my syllabus search. Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-16138465977257423722018-08-30T16:37:23.139-07:002018-08-30T16:37:23.139-07:00Can you possibly email me your syllabus search? I ...Can you possibly email me your syllabus search? I can't open it via the link...Brooklyn-Based Math Teacherhttps://www.blogger.com/profile/10741705084695371179noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-50980056356340419292018-03-29T17:37:37.727-07:002018-03-29T17:37:37.727-07:00https://mikesmathpage.wordpress.com/2014/03/09/sue...https://mikesmathpage.wordpress.com/2014/03/09/sue-van-hattums-optimization-problem/<br /><br />This is so cool! You do not need to be teaching calculus to use this activity!Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-76230680163880756552018-01-15T20:43:00.279-08:002018-01-15T20:43:00.279-08:00Thanks for letting me know they fixed it. I am sti...Thanks for letting me know they fixed it. I am still hoping someone will take me up on my alternate version of the puzzle.Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-55113011703255302782018-01-15T20:00:07.190-08:002018-01-15T20:00:07.190-08:00It seems that they have edited the Nautilus post.
...It seems that they have edited the Nautilus post.<br /><br /><em>* This post was edited to clarify that the question is not posed simultaneously, and that both prisoners know who’s asked first.</em>Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-16550595914397762912017-11-16T08:34:53.898-08:002017-11-16T08:34:53.898-08:00Yes my regression does take the data down to 0. Wh...Yes my regression does take the data down to 0. What algebra steps are used to solve this. I know that at whatever time zero the body is 98.6. ...<br />I got it now. ThanksJosephhttps://www.blogger.com/profile/06455349495917896426noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-16586838878542139622017-11-16T07:04:17.264-08:002017-11-16T07:04:17.264-08:00>The data follows an exponential graph but take...>The data follows an exponential graph but takes the data down to 0.<br /><br />It sounds like you mean that your regression takes the graph down to 0. If you want to use regression, instead of doing the algebra, you would need to use excess heat (how high above room temp) as your y values.<br />Sue VanHattumhttps://www.blogger.com/profile/10237941346154683902noreply@blogger.comtag:blogger.com,1999:blog-5303307482158922565.post-5834537033327713882017-11-16T06:40:04.722-08:002017-11-16T06:40:04.722-08:00I would figure that the temperature would bottom o...I would figure that the temperature would bottom out at room temperature or 80 degrees on the island. Also, I would figure 98.6 being the temperature just prior to death. The data follows an exponential graph but takes the data down to 0. So when the cup of coffee gets to 2 or 3 hours the temp should be room temp but using the model my regression takes it down to zero. <br />I have tried working some transformations using the equation I find but am at a loss as to how to fix the issue. Josephhttps://www.blogger.com/profile/06455349495917896426noreply@blogger.com